A right-angled cone (with base radius $5$ cm and height $12$ cm), as shown in the figure below, is rolled on the ground keeping the point $P$ fixed until the point $Q$ (at the base of the cone, as shown) touches the ground again. By what angle (in radians) about $P$ does the cone travel? $\dfrac{5\pi}{12} \\$ $\dfrac{5\pi}{24} \\$ $\dfrac{24\pi}{5} \\$ $\dfrac{10\pi}{13}$

asked
Feb 27, 2017
in Numerical Ability
Arjun
24.6k points